Need help ASAP Write an equation in whatever form you choose with the given characteristics Perpendicular to y= -1/2x - 8 and passes through: (7. -6)

Step-by-step explanation:

1) Lines that are perpendicular have slopes that are opposite reciprocals of each other. y = -1/2x - 8 is in y = mx + b form, in which the number in place of m represents the slope. So, the slope of y = -1/2x - 8 is -1/2. The opposite reciprocal of it would be (remember to flip the fraction and reverse the sign) 2. So, 2 is the slope we need for the answer.

2) When you know a point that the line must pass through and its slope, you can use point-slope form () to write an equation. and represents the x and y values of the point the line intersects, and m represents the slope. So, substitute 2 for m, 7 for , and -6 for .

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

you have to put the graph on here with the question

step-by-step explanation: