What is the equation of the line that has a slope of 13 and goes through the point (6,−2)? y=13x−8

y=13x

y=13x−4

y=13x+4

{Or, if you mean slope of 1/3:  y = ¹/₃x - 4 }

Step-by-step explanation:

The point-slope form of the equation is y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope:

m = 13

(6, -2)    ⇒   x₀ = 6,  y₀ = -2

The point-slope form of the equation:

y + 2 = 13(x - 6)

So:

y + 2 = 13x - 78        {subtract 2 from both sides}

y = 13x - 80            ←  the slope-intercept form of the equation

{Or, if you mean slope of ¹/₃:  m = ¹/₃

The point-slope form of the equation: y + 2 = ¹/₃(x - 6)

y + 2 = ¹/₃x - 2         {subtract 2 from both sides}

y = ¹/₃x - 4             ←  the slope-intercept form of the equation}

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.