Find the solution to the system of linear equations below.

x - y = 0
3x + 2y = 10


the desired solution is (2, 2)

Step-by-step explanation:

Solve this using elimination by add'n/subtr'n.

Multiply the first equation by 2, obtaining the equivalent set of equations:

2x - 2y = 0

3x + 3y = 10

Combining like terms, we get 5x = 10, and thus x must be 2.

Subbing 2 for x in the first equation yields 2 - y = 0, or y = 2.

Then the desired solution is (2, 2).

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3