One cylinder has a volume that is 8 Centimeters cubed less than StartFraction 7 over 8 EndFraction of the volume of a second cylinder. If the first cylinder’s volume is 216 Centimeters cubed, what is the correct equation and value of x, the volume of the second cylinder? StartFraction 7 over 8 EndFraction x + 8 = 216; x = 182 centimeters cubed
StartFraction 7 over 8 EndFraction x minus 8 = 216; x = 196 centimeters cubed
StartFraction 7 over 8 EndFraction x + 8 = 216; x = 238 centimeters cubed
StartFraction 7 over 8 EndFraction x minus 8 = 216; x = 256 centimeters cubed
Mark this and return

216= 7/8 x L -8

Step-by-step explanation:

Given that,

One cylinder has a volume that is 8cm less than 7/8 of the volume of a second cylinder

The first cylinder’s volume is 216 centimeter cubed

From given,

Let "x" be the volume of second cylinder

Therefore,

Volume of first cylinder = 7/8 of the volume of a second cylinder - 8

Thus the volume of second cylinder is 256 centimeter cubed

what does x eaqual

step-by-step explanation:

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10