In ΔVWX, x = 160 cm, v = 150 cm and ∠W=77°. Find the length of w, to the nearest centimeter. PLEASE HURRY

193

Step-by-step explanation:

according to the question

w²=x²+v²-2xv.cos(<w)

w=√160²+150²-2.160.150.cos(77)°

w=√48100-48000cos(77°)

w=193

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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