Question 3 (2 points) (04.07)

Two separate bacteria populations grow each month and are represented by the functions fx) = 3* and g(x) = 7x + 6. In what month is the f(x)
population greater than the g(x) population? (2 points)

Complete question is;

Two separate bacteria populations grow each month and are represented by the functions f(x) = 3^(x) and g(x) = 7x + 6. In what month is the f(x) population greater than the g(x) population?

A. Month 1

B. Month 2

C. Month 3.

D. Month 4

Option D: Month 4

Step-by-step explanation:

We are given the functions;

f(x) = 3^(x)

And g(x) = 7x + 6

We want to find the month when f(x) > g(x)

Thus;

3^(x) > 7x + 6

For option A, month 1 means x = 1.thus;

LHS is 3¹ = 3

RHS = 7(1) + 6 = 13

Our LHS is not greater than RHS as the question demands, thus this option is not correct

For option B, month 2 means x = 2. thus;

LHS is 3² = 9

RHS = 7(2) + 6 = 20

Our LHS is not greater than RHS as the question demands, thus this option is not correct

For option C, month 3 means x = 3. thus;

LHS is 3³ = 27

RHS = 7(3) + 6 = 27

Our LHS IS equal to the RHS and not greater than RHS as the question demands, thus this option is not correct

For option D, month 4 means x = 4. thus;

LHS is 3⁴ = 81

RHS = 7(4) + 6 = 34

Our LHS is greater than RHS as the question demands, thus this option is correct

66% of the price that was mark on the bottom

-3(b-8)-5=9(b+2)+1

distribute

-3b+24-5=9b+18+1

add/ subtract

-3b+20=9b+19

20-19= 1

-3b+1=9b

9b+3b= 12b

1=12b

1 divided by 12 = 1/12

answer: 1/12 = b