What is the area of the blue coloured triangle ranging from the two squares of 4x4 and 6x6 dimensions?

Area = 18 Sq.units

Step-by-step explanation:

From the given dimensions we have, we can say that the total length of the base = 6 + 4 = 10 units

Now,since we know that all sides of the red square are 6 units, we can use pythagoras theorem to get the length of the long diagonal that serves as the base of the blue colored area.

Let the diagonal be c. Thus;

c = √(10² + 6²)

c = √(100 + 36)

c = √136

Let length of the horizontal part of the blue area be "b". Thus, b = 6 units

Let the other part of the triangle be a. We can find a from pythagoras theorem.

a = √(4² + 6²)

a = √(16 + 36)

a = √52

Using hero's formula, we can find the area of the triangle;

Area = √(s(s − a)(s − b)(s − c))

Where s = (a + b + c)/2

s = (√52 + 6 + √136)/2

s = 12.4365

Area = √(12.4366(12.4365 −√52)(12.4365 − 6)(12.4365 − √136))

Area = 18 Sq.units

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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