Write the equation of the line in slope-intercept form that passes through the point (-3, 5) and is parallel to y = -2/3 x

y= -2/3x+3

Step-by-step explanation:

Parallel lines have the same slope but different y-intercepts.

y=-2/3x is your original equation

Your slope is still -2/3

y=mx+b

y=-2/3x + b

Substitute the points from the coordinates

5 = -2/3(-3) + b

5 = 2 + b

-2   -2

b=3

Your parallel line equation is: y= -2/3x+3

Have a great day!

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.