I will give brainiest to whoever answers correctly !!

$2936.79

Explanation:

The Formula for compounding interest:

F=final amount  (we need to find this)

I=initial amount (900 + 250 + 300 + 1400 = $2850)

r=interest rate  (1% = 0.01)

n=number of times interest applied per time period  (360)

t=number of time periods elapsed (36 months = 3 years)

F = 2850(1.030454105)

F = $2936.79

He will have a total of $2936.79

Step-by-step explanation:

The total to be invested is the addition: 900+250+300+1400=2850

Now we invest this amount at the specified rate for three years (equivalent to 36 months), and use the compounded interest formula:

on your paper it doesn't say the answer but the the answer is altitude

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2