Please hellp :(

1

Step-by-step explanation:

To find the solutions (or, in other words, zeroes) of a quadratic function/equation we use the discriminant (the part that's inside the square root of the quadratic formula, .)

If the discriminant is smaller than 0, there are no zeroes

If the discriminant is equal to 0, there is one zero

If the discriminant is larger than 0, it has two zeroes

The discriminant is commonly denoted as .

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer:

c. the third graph