Arectangle-shaped lot is 26.7 m long and 10 m wide. if fencing comes in 30 m rolls, how many rolls must be bought to fence the lot?

Given:

l (length) = 26.7 meters
w (width) = 10 meters
f (fencing roll) = 30 meters

Find:
Fencing Roll Needed = P ÷ f ; where P is Perimeter

To solve for P:

P = 2 (l + w)

Solution:

We need to find P first.

P = 2 (l + w) ; let's substitute the given sides
P = 2 (26.7 meters + 10 meters)
P = 2 (36.7 meters)
P = 73.4 meters

Now let us apply it to the formula

Fencing Roll Needed = P ÷ f
Fencing Roll Needed = 73.4 meters ÷ 30 meters ; substituting the given numbers. The meter unit will be cancelled out

Fencing Roll Needed = 2.4467

Since you cannot buy that kind of amount in the market:

Fencing Roll Neded ≈ 2.5 or 2 1/2; Final Answer