On a coordinate grid, a grocery store is located at (3,0) and the hardware store is located at (4,3). If the hardware store is the midpoint between the
grocery store and the pharmacy, what is the approximate distance from
the hardware store to the pharmacy? (Note: 1 unit equals 5 miles) *
7.5 miles
15.8 miles
O 79 miles
O 17.5 miles

Hence the required distance is 6.32 units.

Step-by-step explanation:

Given that , On a coordinate grid, a grocery store is located at (3,0) and the hardware store is located at (4,3). If the hardware store is the midpoint between the grocery store and the pharmacy .

And we need to find approximate distance from

the hardware store to the pharmacy .

⇒ Midpoint = ( x1 + x2 )/2 , (y1 + y2 )/2

⇒ 4,3 = (3+x)/2 , (y+0)/2

⇒ 4,3 = (3+x)/2 , y/2

⇒ 4 = 3+x/2

⇒ 3+x = 8

⇒ x = 8-3

⇒ x = 5

⇒ y/2 = 3

⇒ y = 3*2

⇒ y = 6

Hence the coordinate of pharmacy is (5,6)

⇒ Distance = √ [ (x2 -x1 )² + (y2 - y2)² ]

⇒Distance = √ [ (5-3)² + (6-0)² ]

⇒ Distance = √ [ 2² + 6² ]

⇒ Distance= √ 4 + 36

⇒ Distance = √ 40

⇒ Distance = 6.32 units

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: