What eqwation of a parabola with a focus(6,-2) and a directrix x=-2

The equation of the parabola

( y +2 )² = 16 (x-2)

Step-by-step explanation:

Step(i):-

Given the focus of the Parabola ( 6, -2 )

we know that the Focus of the Parabola

                ( h + a , k ) = ( 6 , -2 )

Comparing

              h + a = 6 ...(i)

          and  k = -2

Given directrix of the parabola

           x = -2

The  directrix of the parabola  x = h - a = -2

        h - a = -2 ...(ii)

Adding (i) and (ii) equations , we get

    h + a + h-a = 6 -2

                2 h = 4

           ⇒    h  = 2

Substitute 'h' = 2 in equation (i) , we get

          h + a = 6

          2 + a = 6

                a = 6 -2 =4

Step(ii):-

The equation of the parabola having Vertex ( h,k) = (2 , -2) and a = 4

( y - (-2))² = 4 (4) ( x -2)

Final -

The equation of the parabola

( y +2 )² = 16 (x-2)

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3