An urn contains forty red chips and sixty white chips. Six chips are drawn out and discarded, and a sev- enth chip is drawn. What is the probability that the sev- enth chip is red

The probability that the 7th chip is red = 0.4

Step-by-step explanation:

Given that;

an urn contains 40 red chips and 60 white chips

6 chips are randomly drawn and discarded and a 7th chip is drawn,

lets consider E as the the event that represent the 7th chip is red.

so probability that 7th chip is red will be;

P(E) = ⁶∑ ×  /  

= × + ×  + ......+  /

= [ 2002554400 + ..... + 130504920 ] /

= 44821170240 / (1192052400)(94)

= 44821170240 / 112052925600

= 0.4

Therefore the probability that  the 7th chip is red = 0.4

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation: