Find the probability that the employer gives vacation hours to 3 males and 3 females if she chooses 6 students from the class at random.

This question is incomplete, the complete question is;

An employer has a total of 12 staffs comprising of 7 females and 5 males.

Find the probability that the employer gives vacation hours to 3 males and 3 females if she chooses 6 students from the class at random.

the required probability is 0.3788

Step-by-step explanation:

Given that;

Total number of staffs = 12

7 females and 5 males

now

Total number of ways to 6 staffs from 12  = ¹²C₆

Number of ways of selecting 3 females and 3 males = ⁷C₃ × ⁵C₃

so,

Probability that the employer gives vacation hours to 3 males and 3 females if she chooses 6 students from the class at random will be;

= ⁷C₃ × ⁵C₃ / ¹²C₆

= ( [7!/(3!×(7-3)!] × [5!/(3!×(5-3)!] ) / [12!/(6!×(12-6)!]

= [35 × 10] / 924

= 350 / 924

= 0.3788

Therefore, the required probability is 0.3788

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29