Sandeep likes to skate at an ice cream parlor that is due south of his school and due west of his favorite movie theater. If the ice cream parlor is 8 miles from his school and the straight-line distance between the school and the movie theater is 10 miles, how far is the ice cream parlor from the movie theater?

The ice cream parlor is 12.81 miles far from the movie theatre.

Step-by-step explanation:

Given that:

Distance between school and ice cream parlor = 8 miles

Distance between school and movie theatre = 10 miles

These distances will serve as base and perpendicular of a right angled triangle and the hypotenuse will be the distance between movie theatre and ice cream parlor.

Using Pythagorean theorem;

Taking square root on both sides

Hence,

The ice cream parlor is 12.81 miles far from the movie theatre.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

answer: sorry i can't you.

step-by-step explanation: