You are skiing down a mountain with a vertical height of 650 feet. The distance from the top of the mountain to the base is 1300 feet. What is the angle of elevation from the base to the top of the mountain

The angle of elevation from the base to the top of the mountain is 30°.

Step-by-step explanation:

Given: Vertical height of mountain is 650 feet and the distance from the top of the mountain to the base is 1300 feet.

To find: The angle of elevation from the base to the top of the mountain.

Let AB be the height of mountain and BC be the base.

Then, according to question, AB=650 feet and AC=1300 feet.

Let ∠ACB=.

Then, in ΔABC,

⇒

⇒

⇒°

Hence, the angle of elevation from the base to the top of the mountain is 30°.

1gm = 1000mg so 0.1gm = 1000mg

first, convert the weight to kg

160lb * 1kg/2.2lb = 72.7kg

next, the dose

72.7kg * 100mg/kg = 7270mg

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)