The nth term of a sequence is 3n + 5
write down the 5th and 6th terms of the sequence

5th term = 20

6th term = 23

Step-by-step explanation:

nth term = 3n + 5

Find the 5th term

When n = 5

5th term = 3n + 5

= 3(5) + 5

= 15 + 5

= 20

5th term = 20

Find the 6th term

When n = 6

6th term = 3n + 5

= 3(6) + 5

= 18 + 5

= 23

6th term = 23

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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