Solve for n in the equation 16(3-n) × 2(1+n)=½

2−12n=3n+16 2 - 1 2 n = 3 n + 16. Combine n n and 12 1 2 . 2−n2=3n+16 2 - n 2 = 3 n + 16. Move all terms containing n n to the left side of the equation.

Step-by-step explanation:

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d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

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