A water tank holds 522 gallons but is leaking at a rate of 4 gallons per week. A second water tank holds 696 gallons but is leaking at a rate of 7 gallons per week. After how many
weeks will the amount of water in the two tanks be the same?
The amount of water in the two tanks will be the same in
weeks.

58 weeks

Step-by-step explanation:

Water tank A = 522 - 4x

Water tank B = 696 - 7x

Where,

x = number of weeks

Equate both equations

522 - 4x = 696 - 7x

Collect like terms

522 - 696 = -7x + 4x

-174 = -3x

Divide both sides by - 3

x = -174/-3

x = 58 weeks

The amount of water in the two tanks will be the same in 58

weeks

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.