In the figure below, line Ad is parallel to line Hy and line GK is parallel to line CF. D-
3/4
12
16 15
13/14
5/6
877
9/10
12 11
F
Which argument correctly explains why m23=m29?
m23=mZ15, as they are exterior angles
m 15 =m210, as they are corresponding angles
m210=m29. as they are supplementary angles
o
m23=m28, as they are vertical angles
• m28=m_12. as they are corresponding angles
m212 = 29, as they are adjacent angles
O
m23=m24, as they are adjacent angles
m24 =mZ2, as they are supplementary angles
m22 =m29, as they are alternate interior angles
O
m23 =m22, as they are vertical angles

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier

3/5

step-by-step explanation:

double number line is not a standard concept, so it must have been defined in your textbook. assume top line is numerator.

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %