The expression x3 – 64 can be written as (x)3 – (4)3. What is the factorization of x3 – 64? a3 – b3 = (a – b)(a2 + ab + b2)

A. (x – 4)(x2 + 4x + 8)
B. (x – 4)(x2 + 4x + 16)
C. (x – 64)(x2 + 64x + 16)
D. (x – 64)(x2 + 64x + 4,096)

B

Step-by-step explanation:

(x - 4) because a = x and b = 4, subsitute into (a - b)

(x2 + 4x + 16) because if a = x and b = 4, you subsitute them into (a2 + ab + b2) to get your answer

need more detail

step-by-step explanation:

lele

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x