If the pre image coordinate is G (-8, -2) what is the image coordinate with a dilation of k=LaTeX: \frac{1}{2}1 2? A. G' (-16, -4)

B. G' (-6, 0)

C. G' (-4, -1)

D. None of the Above

Option G'(-4, -1) is correct.

Step-by-step explanation:

Given the coordinates of the point

We know that when an object is dilated by a scale factor, it gets reduced, stretched, or remains the same, depending upon the value of the scale factor.

Rule to calculate the dilation by a scale factor 1/2 centered at the origin

P(x, y) → P'(1/2x, 1/2y)

Here, P'(1/2, 1/2y) is the image of P(x, y).

Thus,

G (-8, -2)  → A'(1/2(-8), 1/2(-2)) = G'(-4, -1)

Therefore, the image coordinates of G (-8, -2)  after dilation by a scale factor of 1/2 will be: G'(-4, -1)

Thus, option G'(-4, -1) is correct.

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

step- i d k and i d c : )

you: : 0

bye