How many solutions does this system of linear equations have? Explain.
1= 2
=1+3 2

There are no real solutions.

Step-by-step explanation:

We have the equation:

x = y^2

y = x + 3/2

To solve this, we can start by noticing that x is already isolated in the first equation, then we can replace it in the second equation to get:

y = y^2 + 3/2

And now we can rewrite this as:

y^2 - y + 3/2 = 0

This is a quadratic equation, and the solutions can be calculated with Bhaskara's equation, the solutions are:

We have a negative number inside the square root, this means that the solutions are complex numbers.

Then we can conclude that the system of equations has no real solutions.

4x and 6y

im not sure though

5

step-by-step explanation: