What is the equation of a line perpendicular to 2x-3y=6 and passes through the point (6,-1) ?

y=-3/2x+8

Step-by-step explanation:

Alright so first we need to convert this equation to Y=mx+b form.

We get y=2/3x-2

In order for it to be perpendicular, we must use -3/2 as the slope.

y=-3/2x+b

Next we need to find the y-intercept of this

Plug in 6 for x and -1 for y and solve for b

b=8

Hope this helps :-)

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

42.4

step-by-step explanation:

convert to decimal