Please help me if you understand the area of a triangle. Look at the screenshot below!

Step-by-step explanation:

In this problem, we will rearrange the equation to isolate .

We start with the given equation:

I will work the and the out of the right side so that is left by itself.

First I multiply both sides by 2 to get rid of the :

2 is the same as , so its numerator and denominator cancel the .

Simplifying, we now have:

Now we can divide both sides by :

We can cancel the in the fraction on the right side, and we're left with:

which is the same as:

Hope this helps! Let me know if you have any questions.

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92