Write a function in the form y=mx+b for the line that contains the points (-6.4, -2.6 )and (5.2,9)

The function in the form y = mx+b will be:

y = x + 3.8

Step-by-step explanation:

We know that the slope-intercept form of the line equation

where

Given the points

Determining the slope between (-6.4, -2.6 )and (5.2,9)

Refine

substituting (5.2, 9) and m = 1 in the slope-intercept form of the line equation

y = mx+b

9 = 1(5.2) + b

b + 5.2 = 9

b = 9 - 5.2

b = 3.8

Therefore, the value of x = 3.8

now substituting b = 3.8 and m = 1 in the slope-intercept form of the line equation

y = mx+b

y = 1(x) + 3.8

y = x + 3.8

Therefore, the function in the form y = mx+b will be:

y = x + 3.8

i hope this is what you were looking for.

see attached graph

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.