Pls help!(: 1. find f(0) and use the function f(x)=2|x+10|-6

2. find x if g(x)=20 use the function g(x)=x+1

3. find g(0)+f(1) using the functions f(x)=2|x+10|-6 and g(x)=x+1

Please explain Im confused..

                                               Question 1)

Given the function

f(x) = 2|x+10| - 6

You need to remember that:

f(x) = y

f(0) means we need to determine the value of y at x = 0.

so substitute x = 0 in the function

Apply absolute value:    

Thus,

                                               Question 2)

Given the fuction

g(x) = x+1

substitute g(x) = 20 in the function

20 = x+1

x = 20-1

x = 19

Thus,

x = 0

                                                  Question 3)

Given the function

f(x)=2|x+10|-6

substitute x = 1 in the function

f(1)=2|1+10|-6

f(1)=2|1+10|-6

f(1) = 2|11| - 6

Apply absolute value:    

f(1) = 2(11) - 6

f(1) = 22 - 6

f(1) = 16

Given the function

g(x)=x+1

substitute x = 0 in the function

g(0) = 0+1

g(0) = 1

Thus,

g(0)+f(1) = 16+1

             = 17

45

step-by-step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐