Find tan (a+B), given cot a= -3/4 , csc B= 25/24 , 90° < a < 180° , 90°< B < 180°

tan(a + B) =

Step-by-step explanation:

cot(a) =

Therefore, tan(a) =

cosec(B) =

Since, 1 + cot²(B) = cosec²(B)

1 + cot²(B) =

cot²(B) =

cot(B) =

          =

tan(B) =

Since, tan and cot of an angle is negative in II quadrant,

Therefore, tan(B) =

Since, tan(a + B) =

By substituting the values in the identity,

tan(a + B) =

                =

                =

                =

                =

Therefore, tan(a + B) = is the answer.

water molecules will move from the side of higher water concentration to the side of lower concentration until both solutions are isotonic. at this point, equilibrium is reached. in an isotonic solution, the flow of water in and out of the cell is happening at the same rate.

hope this < 3

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.