A stadium has 54,000 seats. Seats sell for 30$ in section A,$24 in section B, and $18 in section C. The number of seats in section A equals the total number of seats in section B and C. Suppose the stadium takes in $1,384,800 from each sold -out event. How many seats does each section hold

46160

Step-by-step explanation:

Total price of seats A = 1384800÷2=692400

seats in section A=692400÷30=23080

seats in section B = 23080÷2=11520

seats in section C=23080÷2=11520

Totals seats in the stadium=23080 +11520 +11520 = 46160

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40

c) the median for town a 30" is greater than the median for town b 25"

step-by-step explanation:

town a, median = q2 = 30

town b, median - q2 = 25

so the median for town a 30" is greater than the median for town b 25"