Question 7 of 10 Determine which postulate or theorem can be used to prove
that ASEA = APEN.
A. AAS
B. SAS
C. ASA
D. SSS

Option C

Step-by-step explanation:

From the picture attached,

Given:

SE ≅ EP

∠ESA ≅ ∠ EPN

To Prove:

ΔSEA ≅ ΔPEN

Solution:

             Statements                        Reasons

1). SE ≅ EP                                1). Given

2). ∠ESA ≅ ∠ EPN                   2). Given

3). ∠SEA ≅ ∠NEP                    3). Vertical angles theorem

4). ΔSEA ≅ ΔPEN                    4). By ASA postulate

Therefore, Option C is the correct option.

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source