Mr. And Mrs. Doran have a genetic history such that the probability that a child being born to them with a certain trait is 0.14. If they have seven children, what is the probability that at most two of their seven children will have that trait? Round your answer to the nearest thousandth.

0.938

Step-by-step explanation:

From the question :

p = 0.14

Number of children, n = 7

P(x ≤ 2) = P(2) + P(1) + P(0)

Using binomial probability :

P(x =x) = nCx  * p^x * (1 - p)^(n - x)

We could also use the binomial probability calculator :

P(x ≤ 2) = 0.3479 + 0.3965 + 0.1936

P(x ≤ 2) = 0.938

his chances of getting a coin of higher value is 4/19

step-by-step explanation:

  the correct choice is marked

step-by-step explanation:

the first two graphs show multiple turning points. the last graphs matches the description in every detail.