Find the particular solution to y " = sin(x) given the general solution y = -sin(x) + Ax + B and the initial conditions y (pi / 2) =0 and y'(pi / 2) = -2 -sin(x) +1 + π

-sin(x) - 2x + π

-sin(x) - 2x - π

-sin(x) - 2x + π + 1

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step-by-step explanation:

hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )

answer: idk

step-by-step explanation:

i think the correct option is the second option.