Find the equation of the line passing through point (3,5) and with slope = 1/3 a) y=1/3x+4
b) y=-1/3x+4
c) y=3x-5
d) y=1/3x+5

Step-by-step explanation:

The standard form of equation of a line in point slope form is expresses as

y - y0 = m(x-x0)

m is the slope

(x0, y0) is a point  on the line

Given

m = 1/3

(x0, y0) = (3, 5)

Substitute into the equation

y - 5 = 1/3 (x-3)

3(y-5) - x-3

3y - 15 = x-3

3y = x-3+15

3y = x+12

y = 1/2 x + 12/2

y = 1/3 x + 4

Hence the require equation of the line is y = 1/3 x + 4

a: 1/6, j: 1/4

step-by-step explanation: you are welcome