What is y=6x^2 +96x +388 in vertex form?
please show work

y = 6(x + 8)² + 4

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Using the method of completing the square.

y = 6x² + 96x + 388

The coefficient of the x² term must be 1, so

factor out 6 from 6x² + 96x

y = 6(x² + 16x ) + 388

To complete the square

add/subtract (half the coefficient of the x- term)² to x² + 16x

y = 6(x² + 2(8)x + 64 - 64) + 388

  = 6(x + 8)² - 384 + 388

y = 6(x + 8)² + 4 ← in vertex form

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8