Holiday dinners at June’s house are always a festive occasion. One particular holiday, June has 16 guests. June offers the guests apple pie and blueberry pie. While any guest can have slices of both pies, June never serves a particlar guest more than one slice of each pie and each guest is allowed to decline any slice of pie they don’t care for.

June serves a total of 10 slices of apple pie and a total of 11 slices of blueberry pie.

June serves 8 guests slices of both pies.

How many guests had no pie at all?

a. 3

b.2

c.0

a. 3

Step-by-step explanation:

We solve this question gathering the information given in the question.

June serves 8 guests slices of both pies.

This is soon going to be used

June serves a total of 10 slices of apple pie

This includes the 8 guests which got served both pieces. So 10 - 8 = 2 guests were served only apple pie.

11 slices of blueberry pie.

By the same logic as above, 11 - 8 = 3 guests were served only blueberry pie.

So

8 + 2 + 3 = 13 guests were served at least one pie.

16 - 13 = 3 guests had no pie at all.

the answer would be c:   ax + b = ax + c

step-by-step explanation:

6/20

step-by-step explanation: