Find the sum. one ninth + one twelfth A. 7 over 36 B. six sevenths C. one over thirty-six D. 1 over 7h plz help fast i am stuck. and thank you
12/14/2020

A. 7 over 36

Step-by-step explanation:

One ninth =1/9

One twelfth = 1/12

1/9+ 1/12= 12+9/108

= 21/108

We can then reduce the fraction to the lowest denominator by dividing the numerator and denominator by 3

That will result in 7/36

i'm assuming it's looking for the missing length, which should be 4cm

hope this !

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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