Write the equation of the line, in slope-intercept form, that has a slope of -8/5and contains the point

y = -8/5x + 23/5

Step-by-step explanation:

Complete question

Write the equation of the line, in slope-intercept form, that has a slope of -8/5and contains the point (6, –5)

The equation of a line in pint slope form is expressed as;

y - y0 = m(x-x0)

Given

m = -8/5

(x0, y0) = (6, -5)

Substitute into the formula

y - (-5) = -8/5(x-6)

y+5 = -8/5(x-6)

Multiply through by 5

5(y+5) = -8(x-6)

5y + 25 = -8x + 48

5y = -8x +48 - 25

5y = -8x + 23

y = -8/5x + 23/5

Hence the equation in slope intercept form is y = -8/5x + 23/5

(23*2)-12=x     x=34

step-by-step explanation:

step-by-step explanation: