John has 8 less nickels than dimes. If there is $8.30 in the purse, which equation could be used to determine the number of each type of coin?

So we know that John has 8 less nickels than dimes.

10¢= one dime

5¢= on nickel

8x5=40

Multiply 8 with 5 first because you know John hase 8 less nickels than dimes.

Subtract $8.30 with 40¢. $7.90. $7.90 divide 10 is 79 so then the left over is 0.

Final result: 79 dimes and 8 nickels.

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5