5. (06.03) How can
x - 2 = -x + 8 be set up as a system of equations? (6 points)
5
O 5y – 5x = -10
3y - 3x = 24
O 5y – 5x = -10
3y + 3x = 24
u
5y + x = -10
3y + x = 24
0 5y - x = -10
3y - x =

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

sina-sinb

cosb+cosa

tana-tanb

cos0+cos x pi/3

20tan

step-by-step explanation:

6cm

step-by-step explanation: