Find the limit, if it exists.
Lim (2x^3+x^2+7)
X->2

27

Step-by-step explanation:

In this case, because we have a polynomial where all x-values exist, we can plug the value (x=2) straight into the function:

The limit of (2x^3+x^2+7) as x approaches 2 equals 27, which makes sense since the value of (2x^3+x^2+7) at x = 2 is 27.

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: