Find the slope of the line that passes
through the points (-6, -8) and (-6, 12).

there isn't a slope, because this line isn't even a function, because it is a vertical line... so it doesn't pass the vertical line test...

Step-by-step explanation:

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Step-by-step explanation:

the equation for the slope of the line is (y2-y1)/(x2-x1)

here are the given points: (-6,-8) and (-6,12)

label the points:

x1=-6

y1=-8

x2=-6

y2=12

now substitute into the equation (m is slope)

m=(12--8)/(-6--6)

m=(12+8)/(-6+6)

m=20/0

m=undefined

the slope is undefined because you cannot divide by 0

Hope this helps!

6/20

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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