Hey you ‼️ yeah I unfortunately need your help again these are hard:(

Step-by-step explanation:

The point of this question is to find out the point where two lines intersect. First we need to get the equation of those lines

Slope of line 1:

(Yb -Ya)/(Xb - Xa) =

(-10 - (-14))/(-1 - (-3)) =

4/2 =

2

Use that slope to find the Y-intercept of line 1

y = 2x + b

-14 = 2(-3) +b

-14 = -6 + b

-8 = b

Therefore Line 1 is:

y = 2x - 8

Slope of line 2

(11 - 13)/(-1 - (-3)) =

-2/2 =

-1

Y-intercept of line 2

y = -x + b

13 = -(-3) +b

13 = 3 + b

10 = b

Therefore line 2 is

y = -x + 10

Now we have 2 equations to solve for the coordinates x and y

y = 2x - 8

y = -x + 10

Substitute y out in one of the equations

2x - 8 = -x + 10

3x = 18

x = 6

Plug x into one of the equations

y = 2(6) - 8

y = 12 - 8

y = 4

Therefore the solution is:

x=6, y=4

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.