The sum of two odd consecutive integers is 88. Find the integers.

-- there is an equation to find this: (2n + 1) + (2n + 3) = (whatever number is given as their sum)

use the equation: 2n + 1 is an odd interger, 2n + 3 is the next odd integer.

(2n + 1) + (2n + 3) = 88

add like terms.

4n + 4 = 88

4n = 84

n = 21

now plugin.

2(21) + 1

42 + 1

= 43 (the first odd integer)

this means the second one would be 45.

43 and 45

add them to check:

43 + 45 = 88

b mark me branliest thx

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116