Find the remainder when the function is

according to the question

3x-1=0

3x=1

x=⅓

so

f(x)=18x³+x-1

f(⅓)=18.(⅓)³+⅓-1

f(⅓)=18.⅓.⅓.⅓+⅓-1

f(⅓)=6.⅑+⅓-1

f(⅓)=⅔+½-1

f(⅓)=0

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

sorry

step-by-step explanation:

sorry, but im pretty sure its a now that i look at it