Let p=x^2-7p=x 2 −7p, equals, x, squared, minus, 7. Which equation is equivalent to (x^2-7)^2-4x^2+28=5(x 2 −7) 2 −4x 2 +28=5left parenthesis, x, squared, minus, 7, right parenthesis, squared, minus, 4, x, squared, plus, 28, equals, 5 in terms of ppp ? Choose 1 Choose 1 (Choice A) A p^2+4p-5=0p 2 +4p−5=0p, squared, plus, 4, p, minus, 5, equals, 0 (Choice B) B p^2-4p+23=0p 2 −4p+23=0p, squared, minus, 4, p, plus, 23, equals, 0 (Choice C) C p^2-4p-5=0p 2 −4p−5=0p, squared, minus, 4, p, minus, 5, equals, 0 (Choice D) D p^2+4p+23=0p 2 +4p+23=0 Help Plz