Help At the bottom of the screen it says "the equation that models the situation is..."

y-y1 = m(x-x1) — point-intercept form

Given both x1 and y1 = coordinate point.

First we have to find the slope by using rise over run. (y2-y1)/(x2-x1) = m

The slope should be m = -4 then we substitute m-value in point-slope form.

y-y1=-4(x-x1) — new equation. After substituting slope in, we need to find the coordinate point that is part of the graph. You can use any points that are given in the picture. I will use point F or (5,0).

Then we substitute x1 = 5 and y1 = 0 in the point-slope form

y-0=-4(x-5) — point-slope form

y=-4x+20 — slope-intercept form..

How about we change to another coordinate point to substitute in? We can check if these points also give same equation (slope-intercept).

Let's substitute (4,4) in the equation.

y-4=-4(x-4)

y=-4x+16+4

y=-4x+20

Same answer. Meaning that all these points that are shown can be substituted in the equation and get the same slope intercept form.

Therefore, point-slope form for the graph can be

y-4=-4(x-4)

you can also change the coordinate point value.

idk

step-by-step explanation:

c: lkllmn.

hope it's you