2.14a +1.b25

c.865

how do I solve this and what are the answers for a. b. and c.

a=0, b=7, c=3

Step-by-step explanation:

Addition

The following addition is shown, where a,b, and c are unknown:

 2.14a

+ 1.b25

  c.865

We'll determine the values of the unknown variables by following the rules of addition.

The last column shows a+5=5. Since a cannot be greater than 9, thus a must be 0.

a = 0

This sum produces no carry.

Now we have 4 + 2 = 6

This is already correct and no variable needs to be calculated

Now we have 1 + b = 8. This leads to b=8-1=7

b = 7

This sum produces no carry.

Finally: 2 + 1 = c. This implies that

c=3

Substituting in the addition:

 2.140

+ 1.725

  3.865

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.