Isabelle has $5.45 in her purse. If she has five more nickels than dimes, and twice as many quarters than dimes, how many of each type of coin does she have?

Nickel = 13

Dimes = 8

Quarters = 16

Step-by-step explanation:

Let N denote Nickel,

Let D denote dime

Let Q denote quarter

Now, from online conversions;

1 nickel = 5 cents

Also, 1 dime = 10 cents

Also, 1 quarter = 25 cents

Isabelle has $5.45 which is also 545 cents.

Thus, we have;

5N + 10D + 25Q = 545 - - - (eq 1)

We are told that;

she has five more nickels than dimes, and twice as many quarters than dimes.

Thus;

N = D + 5

Also, Q = 2D

Plugging them for N and Q in eq 1 givens;

5(D +5) + 10D + 25(2D) = 545

5D + 25 + 10D + 50D = 545

25 + 65D = 545

65D = 545 - 25

65D = 520

D = 520/65

D = 8

Thus; N = D + 5 = 8 + 5 = 13

Q = 2D = 2 × 8 = 16

the correct answer is d

hope this