What is the difference x/x^2+3+2 - 1/(x+2)(x+1)

#4,   x-1/(x^2+3x+2)

Step-by-step explanation:

x/(x^2+3x+2) - 1/((x+2)(x+1))

Convert the 1/((x+2)(x+1)) to 1/(x^2+3x+2)

now you have a common denominator to subtract

x/(x^2+3x+2) - 1/(x^2+3x+2)

results x-1/(x^2+3x+2)

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~

need more detail

step-by-step explanation:

lele